Final answer:
To show that hk is in span, we need to find scalars x and y such that ax + by = h and bx + ay = k.
Step-by-step explanation:
To show that hk is in span, we need to determine if it can be written as a linear combination of the vectors in the span. Let's assume that u = vector a and v = vector b. We need to find scalars x and y such that x*u + y*v = hk.
Using vector addition and scalar multiplication, we have (ax + by)*u + (bx + ay)*v = hk. Rearranging the terms, we get (ax + by)*u + (bx + ay)*v = h(u + v) + k(u - v).
Thus, we can see that hk is in span if we can find scalars x and y such that ax + by = h and bx + ay = k.