Question

Assume each choice below shows the addition of two 6-bit fixed-point binary integers. Mark every choice that results in overflow. FYI: Be certain; Canvas deducts points for incorrect choices.

1) Choice A: 011011 + 010101
2) Choice B: 101010 + 110011
3) Choice C: 111111 + 000001
4) Choice D: 100000 + 011111

Answer 1

In the task of adding two 6-bit fixed-point binary integers, overflow occurs in Choices B and C, where the sums require a seventh bit to be accurately represented which exceeds the 6-bit limit.Option B &C are correct answers.

Step-by-step explanation:

The question asks about the overflow in the addition of two 6-bit fixed-point binary integers. Overflow occurs in binary addition when the sum exceeds the maximum number that can be represented with the given number of bits. In a 6-bit system, the largest number we can represent is 111111 (binary), which is equal to 63 (decimal). When adding two binary numbers, if the result requires a seventh bit to be represented accurately, this means an overflow has occurred.

1. Choice A: 011011 + 010101 = 101100 (no overflow, as result is within 6 bits)
2. Choice B: 101010 + 110011 = 1011101 (overflow, as result is 7 bits)
3. Choice C: 111111 + 000001 = 1000000 (overflow, as result is 7 bits)
4. Choice D: 100000 + 011111 = 111111 (no overflow, as result is within 6 bits)

Choices B and C result in overflow.