Question

A normally distributed set of population scores has a mean of 65 and a standard deviation of 10.2. The standard error of the mean, for samples of size 48 equals...

a. 1.47
b. 10.2
c. 65
d. none of the above

Answer 1

The standard error of the mean (SEM) is a measure of the variability of the sample means when sampling from a population. It is calculated by dividing the standard deviation of the population by the square root of the sample size. In this case, the population has a standard deviation of 10.2 and the sample size is 48, so the calculation is SEM = 10.2 / √48 = 1.47. Therefore, the standard error of the mean for samples of size 48 is 1.47.

Step-by-step explanation:

The standard error of the mean (SEM) is a measure of the variability of the sample means when sampling from a population. It is calculated by dividing the standard deviation of the population by the square root of the sample size. In this case, the population has a standard deviation of 10.2 and the sample size is 48, so the calculation is:

SEM = 10.2 / √48 = 1.47

Therefore, the standard error of the mean for samples of size 48 is 1.47. So, the correct answer is a. 1.47.