Question

A sample of neon gas is held at 25.0 oC and 1.0 atm in a

cylinder with a movable piston. Under these conditions
the gas occupies 5.0 L. What volume does the gas
occupy at 12.5 ºC and 1.0 atm?

Answer 1

Using Charles's Law, which states that volume and temperature are directly proportional at constant pressure, we calculated that neon gas at 12.5 °C and 1.0 atm will occupy a volume of approximately 4.78 L,

Step-by-step explanation:

The question pertains to the behavior of neon gas under varying conditions of temperature, maintaining a constant pressure of 1.0 atm. This is a typical application of Charles's Law, which relates volume and temperature of a gas kept at constant pressure. Charles's Law is usually expressed as V1/T1 = V2/T2, where V refers to volume and T refers to temperature in Kelvin.

To find the volume the neon gas will occupy at 12.5 °C (285.65 K), we first need to convert the initial temperature from Celsius to Kelvin: T1 = 25.0 °C = 298.15 K. The initial volume, V1, is 5.0 L. Using Charles's Law, we solve for V2 as follows:

V2 = (V1 × T2) / T1
V2 = (5.0 L × 285.65 K) / 298.15 K = 4.78 L

Hence, at 12.5 °C and 1.0 atm, the neon gas will occupy a volume of approximately 4.78 L.