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A 7.00 L tank at -3.9°C is filled with 16.9 g of chlorine pentafluoride gas and 11.8 g of sulfur tetrafluoride gas. What is the mole fraction of each gas?

A. XClF5 = 0.54; XSF4 = 0.46
B. XClF5 = 0.46; XSF4 = 0.54
C. XClF5 = 0.59; XSF4 = 0.41
D. XClF5 = 0.84; XSF4 = 0.16
E. XClF5 = 0.16; XSF4 = 0.84

1 Answer

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Final answer:

To find the mole fraction of each gas, calculate the moles of each gas using their molar masses and divide it by the total moles of both gases. The mole fraction of ClF5 is approximately 0.54 and the mole fraction of SF4 is approximately 0.46.

Step-by-step explanation:

To find the mole fraction of each gas, we need to calculate the moles of each gas using their molar masses and then divide it by the total moles of both gases. First, calculate the moles of chlorine pentafluoride (ClF5) and sulfur tetrafluoride (SF4) using their molar masses:

Moles of ClF5 = mass of ClF5 / molar mass of ClF5

Moles of SF4 = mass of SF4 / molar mass of SF4

Next, calculate the total moles of both gases:

Total moles = moles of ClF5 + moles of SF4

Finally, calculate the mole fraction of each gas:

Mole fraction of ClF5 = moles of ClF5 / total moles

Mole fraction of SF4 = moles of SF4 / total moles

Using the given masses and molar masses:

Moles of ClF5 = 16.9 g / (35.453 g/mol + 5 × 18.998 g/mol)

Moles of SF4 = 11.8 g / (32.06 g/mol + 4 × 18.998 g/mol)

Total moles = moles of ClF5 + moles of SF4

Mole fraction of ClF5 = moles of ClF5 / total moles

Mole fraction of SF4 = moles of SF4 / total moles

After calculating the values, we find that the mole fraction of ClF5 is approximately 0.54 and the mole fraction of SF4 is approximately 0.46. Therefore, the correct answer is A. XClF5 = 0.54; XSF4 = 0.46.

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