Question

What volume of carbon dioxide gas is produced by the combustion of 0.410 kg of dodecane (C12H26) gas at 14°C under exactly 1 atm of pressure?

A. 35.5 L
B. 4.74 L
C. 680 L
D. 1330 L
E. 56.9 L

Answer 1

To find the volume of carbon dioxide produced from burning dodecane, convert the mass of dodecane to moles, use the balanced combustion equation to find moles of CO2,

Step-by-step explanation:

To determine the volume of carbon dioxide gas produced by the combustion of 0.410 kg of dodecane (C12H26), we must perform the following steps:

1. Convert the mass of dodecane to moles using its molar mass (170.34 g/mol).
2. Balance the combustion reaction equation: C12H26 + 18.5O2 → 12CO2 + 13H2O.
3. Determine the number of moles of CO2 produced using stoichiometry.
4. Use the Ideal Gas Law (PV=nRT) to calculate the volume of CO2 at the given temperature (14°C) and pressure (1 atm), while converting the temperature to Kelvin.

The volume of CO2 can be calculated using the relation that at STP (0°C and 1 atm), 1 mole of an ideal gas occupies 22.414 liters.then apply the Ideal Gas Law considering the specific temperature and pressure.