Question

Repeat problem 2.2-4 for the differential equation (d² 4d 4)y(t) = dx(t) with initial conditions y0(0-) = 3 and y'(0-) = -4.

Answer 1

To solve the given differential equation, we can use the same method as before. Substitute the given values into the equations and solve for y.

Step-by-step explanation:

To repeat problem 2.2-4 for the given differential equation (d² + 4d + 4)y(t) = dx(t), we can apply the same method as before.

First, we solve the quadratic equation by substituting 2.0 for x and solving for y:

(2.0 + y) * y = 10^-14
y = 4.1 x 10^-8

Then, substituting y = 4.1 x 10^-8 into Equation 15.9.30 and approximating 0.0010-x as 0.0010, we have:

(x + 4.1 x 10^-8) * 0.0010