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Find an equation of the tangent line to the curve y = x² that is parallel to the line y = 39x?

User Adbdkb
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Final answer:

The equation of the tangent line is: y - 380.25 = 39(x - 19.5).

Step-by-step explanation:

To find an equation of the tangent line to the curve y = x² that is parallel to the line y = 39x, we first need to identify the slope of the given line. The slope of the line y = 39x is 39.

Since parallel lines have the same slope, the tangent line to the curve will also have a slope of 39.

Next, we need to find the point on the curve y = x² where the slope of the tangent line is 39.

To do this, we find the derivative of y = x², which gives us 2x.

Setting the derivative equal to 39, we get 2x = 39, solving which yields x = 19.5.

Now, we calculate the y-value on the curve at x = 19.5, which equals (19.5)² = 380.25.

Thus, the point of tangency is (19.5, 380.25). Using the point-slope form of a line, the equation of the tangent line is y - 380.25 = 39(x - 19.5).

User Olaseni
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