Final answer:
To find the required amount of chlorine to react with 500 kg of platinum for cisplatin production, calculate the moles of platinum and then use stoichiometry to determine the moles and mass of chlorine.
Step-by-step explanation:
The student asks about the amount of chlorine, Cl2, needed to react completely with 500 kg of platinum, Pt, to make the anti-cancer drug cisplatin, which is chemically known as PtCl2(NH3)2. Cisplatin is a platinum complex that was discovered to inhibit cell division, making it an effective agent in the treatment of certain forms of cancer. The molecular formula of cisplatin indicates that for each mole of platinum, two moles of chlorine are required. Therefore, to find the amount of chlorine needed, we must first calculate the number of moles of platinum, as the molar mass of platinum is 195.08 g/mol. Once we have the moles of platinum, we can use stoichiometry to calculate the required moles of chlorine, and subsequently the mass of chlorine needed.
To determine how much chlorine (Cl2) is needed to react completely with 500 kg of platinum (Pt) to make cisplatin (PtCl2(NH3)2), we need to use stoichiometry and the balanced chemical equation of the reaction. From the balanced equation, we know that 1 mole of platinum reacts with 1 mole of chlorine to produce 1 mole of cisplatin. We need to convert the mass of platinum to moles using its molar mass and then use the mole ratio to find the moles of chlorine required. Finally, we can convert the moles of chlorine to grams by multiplying by its molar mass.