Question

A proton is accelerated at 3.6x10 raise to the power of 15 metres per seconds square through a distance of 3.5cm. If the initial velocity is 2.4x10 raise to the power of 7 metres per seconds, find the change in kinetic energy at the end of the distance. ( Take mass of proton to be 1.67x10 raise to the power of -27 kilograms).

Answer 1

To find the change in kinetic energy, use the equation: Change in kinetic energy = (final kinetic energy) - (initial kinetic energy).

Step-by-step explanation:

To find the change in kinetic energy, we can use the equation:

Change in kinetic energy = (final kinetic energy) - (initial kinetic energy)

First, let's find the final kinetic energy. We can use the equation:

Final kinetic energy = 1/2 * mass * (final velocity)^2

Given that the mass of the proton is 1.67x10^-27 kg and the final velocity is the initial velocity plus the product of acceleration and distance, which is (2.4x10^7 m/s) + (3.6x10^15 m/s^2 * 0.035 m), we can calculate the final kinetic energy. Then, we can use the initial velocity to find the initial kinetic energy using the same equation. Finally, we can subtract the initial kinetic energy from the final kinetic energy to find the change in kinetic energy.