Final answer:
The value of delta E for the n=3 to n=2 transition in the hydrogen atom is -1.89 eV.
Step-by-step explanation:
The value of delta E for the n=3 to n=2 transition in the hydrogen atom can be calculated using the formula:
Delta E = En=2 - En=3
According to the Bohr Theory, the energy levels in hydrogen are given by the equation:
En = -13.6 eV / n2
Substituting the values, we have:
En=2 = -13.6 eV / (22) = -3.4 eV
En=3 = -13.6 eV / (32) = -1.51 eV
Therefore, the value of delta E is:
Delta E = -3.4 eV - (-1.51 eV) = -1.89 eV