Final answer:
The voltage drop across the 6 ohm resistor is 4.5 V.
Step-by-step explanation:
According to Ohm's law, the voltage drop, V, across a resistor when a current flows through it is calculated using the equation V = IR, where I equals the current in amps (A) and R is the resistance in ohms (2). In this case, we have a 6 ohm resistor. The current flowing through the circuit can be found by using Ohm's law and the total resistance of the circuit. The total resistance is the sum of the resistances of all the resistors connected in series. So, in this case, the total resistance is 2 + 6 + 8 = 16 ohms. The current flowing through the circuit is given by I = V / R, where V is the voltage of the battery (12V) and R is the total resistance (16 ohms). Substituting these values we find, I = 12 / 16 = 0.75A. Now, we can calculate the voltage drop across the 6 ohm resistor using Ohm's law: V = IR. Substituting the values, V = 0.75 x 6 = 4.5V.