Question

A 600 mL bulb containing 0.59 grams of neon and an unknown amount of argon has a pressure of 1.25 bar at 295 K. What is the mass of argon (in grams) in the bulb? R=0.08314 L bar K-1 mol-1

Answer 1

To calculate the mass of argon in the bulb, we first determine the number of moles of neon using the ideal gas law equation. We then calculate the mass of the neon and subtract it from the total mass given to find the mass of argon. The mass of argon in the bulb is -0.03 grams.

Step-by-step explanation:

To solve this problem, we need to use the ideal gas law equation: PV = nRT. Given the pressure, volume, and temperature, we can first calculate the number of moles of neon using the equation n = (PV) / (RT). Once we have the number of moles of neon, we can calculate its mass using the equation mass = moles * molar mass. Subtracting the mass of neon from the total mass given, we can find the mass of argon in the bulb.

Let's start by calculating the number of moles of neon:

n = (1.25 bar * 0.6 L) / (0.08314 L bar K-1 mol-1 * 295 K) = 0.0306 mol neon

Next, we can calculate the mass of neon:

mass of neon = 0.0306 mol * 20.18 g/mol = 0.62 g neon

Now, we subtract the mass of neon from the total mass given:

mass of argon = 0.59 g - 0.62 g = -0.03 g argon

Therefore, the mass of argon in the bulb is -0.03 grams.