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Consider five independently assorting gene pairs, A/a, B/b, C/c, D/d, and E/e, where each demonstrates complete dominance (A_, B_, C_, D_, and E_) and recessiveness (aa, bb, cc, dd, and ee). An individual with genotype AaBbCCddEe is crossed to an individual with genotype AABbCcDdEe. What is the probability of obtaining an offspring with genotype AABbCcDdee?

A. 1/64
B. 1/32
C. 1/16
D. 1/8

1 Answer

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Final answer:

To determine the probability of obtaining an offspring with genotype AABbCcDdee from a cross between AaBbCCddEe and AABbCcDdEe, we analyze the chance of each allele being passed on. However, since one parent can only pass on 'E' and no 'e', it's impossible to obtain the 'ee' configuration, hence the probability is 0.

Step-by-step explanation:

The question considers the inheritance of traits according to Mendelian genetics. To find the probability of an offspring with genotype AABbCcDdee when individuals with genotypes AaBbCCddEe and AABbCcDdEe are crossed, we need to calculate the probability of each gene being passed on from both parents.

  • For gene A, the first parent can only pass on 'a', and the second can pass on 'A' 100% of the time. Therefore, the offspring will always have 'Aa'.
  • For gene B, both parents can pass on 'B' or 'b'. The first parent has a 1/2 chance of passing on 'B' and so does the second parent. The chance of 'Bb' is 1/2 * 1/2 = 1/4.
  • For gene C, the first parent can only pass on 'C' and the second has a 1/2 chance of passing 'c'. Thus, getting 'Cc' is a 1/2 chance.
  • For gene D, the first parent can only pass on 'd' and the second parent has a 1/2 chance of passing 'd', making the probability of 'dd' 1/2.
  • For gene E, the first parent has a 1/2 chance of passing on 'e' and the second parent can only pass on 'E', so there is no way to achieve the 'ee' needed for the given genotype.

Thus, the overall probability of achieving the genotype AABbCcDdee is 0 because it's not possible to get 'ee' from these parents.

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