Final answer:
The entropy change (ΔS) for the oxidation of glucose is positive, mainly due to the increase in number and mass of gaseous molecules, indicating increased disorder in the system.
Step-by-step explanation:
The expected entropy change (ΔS) for the oxidation of glucose to carbon dioxide and water would be positive. This is because the reaction results in an increase in the number of gaseous molecules, going from 6 molecules of O₂ to 12 molecules (6 CO₂ + 6 H₂O) in the products. According to Figure 14.3.6, the positive entropy change is due mainly to the greater mass of CO₂ molecules compared to those of O₂, which suggests a dispersal of energy and increased randomness or disorder in the system. The fact that the reaction is spontaneous and exothermic (as shown by the negative ΔG and ΔH values) also typically correlates with a positive entropy change. Therefore, option C) is the correct answer. It is important to note that heat release, in itself, is not a direct indicator of entropy change; the key factor is the increase in disorder, mainly manifested by the increased number of gas particles.