Final answer:
To determine if the genes are in repulsion, we must look at the occurrence of recombinant genotypes. Recombinant types like aB and Ab suggest recombination, indicating that the genes may not be in complete linkage repulsion but without further data, a definitive answer cannot be given. Option b) False is the correct answer.
Step-by-step explanation:
When considering genetic inheritance and chromosome linkage, it's important to distinguish between genotype and phenotype. A genotype represents the genetic makeup of an organism, whereas a phenotype refers to the physical expression of traits.
In a situation where two genes A and B are linked and located on the same chromosome, the parental genotype would be AB/ab, which means that the offspring could show recombinant types due to crossing over during meiosis. The question posed refers to a set of genotypic frequencies and asks if the genes are in repulsion, which is another way of saying separated by recombination.
An observed ratio significantly different from what is expected from unlinked genes may suggest linkage or repulsion due to crossing over. In the given genotypic data, nonparental types are observed, such as aB and Ab, which can only occur if there is recombination, thereby indicating that the genes are not completely linked in repulsion. True linkage would not result in these genotypes. Considering the problem data and the Mendelian laws of inheritance for linked and unlinked genes, specifically the concept of independent assortment and expected genotypic ratios, the correct conclusion can be made.
To answer the student's question, more context or data is necessary to determine whether or not the genes are truly in repulsion. However, based on the principles of inheritance, if we observe a significant number of recombinant genotypes, this suggests that recombination does occur, and the genes are not in complete linkage repulsion. Hence, without additional context, a definitive answer cannot be provided to the student's question.