Final answer:
The color-blind woman with Turner syndrome must have inherited the color blind allele from her color blind father and the Turner syndrome resulted from nondisjunction in her mother during meiosis.
Step-by-step explanation:
In the case of the color-blind woman with Turner syndrome (XO), her condition can be explained by two separate events. Her color blindness is explained by X-linked recessive inheritance.
Since colorblindness is recessive, she would have to inherit two alleles for the condition to express it. However, because Turner syndrome is characterized by having only one X chromosome (XO instead of XX), the presence of Turner syndrome likely resulted from nondisjunction during her mother's meiosis, where one of her gametes did not receive any of the X chromosomes.
Her father being color blind indicates that his X chromosome carries the allele for colorblindness. Since her father can only pass his X chromosome to his daughters, she must have inherited the colorblind allele from him. Hence, the likely explanation for her conditions is option B) nondisjunction in the father at meiosis I for the colorblind gene inheritance and option C) nondisjunction in the mother in meiosis I or II for Turner syndrome. The father's nondisjunction would not result in Turner syndrome, as he only carries one X chromosome and any failure to separate would result in an XY or an OY gamete, which are not viable or do not result in Turner syndrome.