Question

Determine the volume of 0.170 M

NaOH
solution required to neutralize each sample of hydrochloric acid. The neutralization reaction is: NaOH(aq)+HCl(aq)→H2O(l)+NaCl(aq)
30 mL
of a 0.170 M
HCl
solution
Express your answer to two significant figures and include the appropriate units.

Answer 1

30 mL of a 0.170 M NaOH solution is required to neutralize 30 mL of a 0.170 M HCl solution, due to the 1:1 molar ratio in the neutralization reaction.

Step-by-step explanation:

To determine the volume of NaOH solution required to neutralize 30 mL of a 0.170 M HCl solution, we need to use the balanced chemical reaction:

NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq)

Since NaOH and HCl react in a 1:1 molar ratio, we can calculate the moles of HCl in the given volume and infer the same number of moles of NaOH needed for neutralization:

# mol HCl = 0.030 L * 0.170 M = 0.0051 mol

Using the molarity of the NaOH solution, we find the volume:

volume NaOH = 0.0051 mol / 0.170 M = 0.030 L or 30 mL

So, we need 30 mL of 0.170 M NaOH to neutralize 30 mL of a 0.170 M HCl solution.