Question

A body of mass 20kg initially at rest is subjected to a force of 40m for 15sec. Calculate the change in k.e

Answer 1

Explanation:kE =10kg(7.3m²/s²)

=73J

Answer 2

Step-by-step explanation:

mass(m)=20kg

velocity(v)=d/t=2.67

k.e=?

now,

k.e=1/2mv^2

=1/2*20*(2.67)^2

=71J