Question

A soccer ball with a mass of 0.464 kg is approaching a player with a velocity of 15.8 m/s Horizontally. Another player strikes the ball, causing it to move in the opposite direction 14.8 m/s If the second player provides 15,884N of force on the ball, how long was the ball in contact with his foot?

Answer 1

The ball was in contact with the player's foot for approximately 1122.86 seconds.

Step-by-step explanation:

To calculate the time the ball was in contact with the foot, we can use the formula:

t = F / ΔP

Where t is the time in seconds, F is the force in Newtons, and ΔP is the change in momentum in kg·m/s.

First, we need to find the change in momentum (ΔP) of the ball. The initial momentum of the ball can be calculated using the formula:

Pi = m * vi

Where Pi is the initial momentum, m is the mass of the ball, and vi is the initial velocity of the ball. Substituting the given values:

Pi = (0.464 kg) * (15.8 m/s)

= 7.3152 kg·m/s

Solving for the final momentum (Pf) using the same formula:

Pf = m * vf

Where Pf is the final momentum, vf is the final velocity of the ball. Substituting the given values:

Pf = (0.464 kg) * (-14.8 m/s)

= -6.8432 kg·m/s

Now, we can calculate the change in momentum:

ΔP = Pf - Pi = (-6.8432 kg·m/s) - (7.3152 kg·m/s)

= -14.1584 kg·m/s

Finally, we can substitute the values into the formula for time:

t = F / ΔP = (15884 N) / (-14.1584 kg·m/s)

≈ -1122.86 s

Since time cannot be negative, we discard the negative sign and the value of t is approximately 1122.86 seconds.