Question

5. If the reaction of carbon monoxide and oxygen gas in question 2

produced 7.03E24 molecules of CO2, what is the mass in grams? Use
44g/mol for M.M. of CO2 and round your answer to the nearest whole
number. *

Answer 1

Answer: The mass in grams is 514.8.

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadros number}}`

given molecules =
`7.03* 10^(24)`

Putting in the values we get:

`\text{Number of moles}=(7.03* 10^(24))/(6.023* 10^(23))=11.7moles`

mass of
`CO_2=moles* {\text {Molar mass}}=11.7mol* 44g/mol=514.8g`

The mass in grams is 514.8.