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What is the most common and deadly form of bone cancer?

A) Rickets
B) Osteomyelitis
C) Osteosarcoma
D) Osteomalacia

User Shaneek
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Final answer:

Osteosarcoma is the most common and deadly form of bone cancer, typically affecting young individuals. It's distinct from other bone conditions such as Rickets, involving vitamin D deficiency, or Osteomalacia, with bone softening. Osteoporosis, a separate condition, is characterized by brittle and weakened bones due to an imbalance in bone remodeling processes.

Step-by-step explanation:

The most common and deadly form of bone cancer is C) Osteosarcoma. Osteosarcoma is a type of bone cancer that typically develops in the osteoblast cells that form the outer layer of bone. It is most frequently diagnosed in teenagers and young adults, often during periods of rapid growth. Unlike other bone diseases such as Rickets, which is characterized by improper bone development due to a vitamin D deficiency, or Osteomalacia, which involves a softening of the bones, osteosarcoma is a malignant tumor that aggressively affects bone tissue.

Osteoporosis, another skeletal system disorder, is a condition in which bones become weak and brittle due to an imbalance between bone formation and bone resorption, which are processes involved in bone remodeling. It is diagnosed by comparing a patient's bone density against peak bone density levels. Risk factors for osteoporosis include age, gender (women are more affected), family history, body frame size, and certain lifestyle choices and medical conditions. Although osteoporosis itself is not fatal, it leads to increased risk of fractures, which can have severe consequences, especially in the elderly.

User Werbary
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