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If K is the midpoint of ER, EK = x + 5, and ER = 4x + 2, what is the length of KR?

If K is the midpoint of ER, EK = x + 5, and ER = 4x + 2, what is the length of KR-example-1
User Mayur
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1 Answer

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Answer:

Explanation:

EK = ½ER

x+5 = ½(4x+2)

x+5 = 2x+1

x=4

User Vasiliy
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