172k views
6 votes
If K is the midpoint of ER, EK = x + 5, and ER = 4x + 2, what is the length of KR?

If K is the midpoint of ER, EK = x + 5, and ER = 4x + 2, what is the length of KR-example-1
User Mayur
by
4.5k points

1 Answer

4 votes

Answer:

Explanation:

EK = ½ER

x+5 = ½(4x+2)

x+5 = 2x+1

x=4

User Vasiliy
by
4.5k points