Question

Given that Avogadro's number is 6.02 x 10²³ particles (atoms, molecules, etc) per mole. What is the mass (in grams) of a sample of NCl_3 that contains 3.9 x 10²² molecules?

A. 100.64
B. 25.16
C. 15.06
D. 10.02

Answer 1

To find the mass of a sample of NCl3 that contains 3.9 x 1022 molecules, you can use Avogadro's number and the molar mass of NCl3. The mass of the sample is approximately 7.4 g.

Step-by-step explanation:

To find the mass of a sample of NCl3 that contains 3.9 x 1022 molecules, we need to use Avogadro's number and the molar mass of NCl3.

Avogadro's number, NA, is equal to 6.02 x 1023 particles per mole. This means that one mole of any substance contains 6.02 x 1023 particles.

The molar mass of NCl3 can be calculated by adding up the atomic masses of nitrogen (N) and chlorine (Cl). The atomic masses of N and Cl are 14.01 g/mol and 35.45 g/mol, respectively. Therefore, the molar mass of NCl3 is (14.01 g/mol) + 3(35.45 g/mol) = 114.36 g/mol.

To find the mass of the given sample, we can use the following equation:

Mass = (Number of molecules) x (Molar mass) / (Avogadro's number)

Plugging in the values: Mass = (3.9 x 1022 molecules) x (114.36 g/mol) / (6.02 x 1023 molecules/mol)

Simplifying the calculation, we find that the mass of the sample is approximately 7.4 g.