Question

4. Find the zeros of: 2x² + 14 = 70 ​

Answer 1

• x = 2√7

• x = -2√7

or

• ± 2√(7)

Explanation:

To find the zeros of the given equation, 2x² + 14 = 70, let's start by subtracting 14 from both sides of the equation to isolate the term with x²:

• 
  `\sf 2x^2 + 14 - 14 = 70 - 14`

Simplify:-

• 
  `\sf 2x^2= 56`

Divide both sides by 2:-

• 
  `\sf \cfrac{2x^2}{2} =\cfrac{56}{2}`

Simplify:-

• 
  `\sf x^2 = 28`

Now, to find the zeros take the square root of both sides of the equation:-

• 
  `\sf x = \pm √(28)`

Simplify:-

• 
  `\sf x=\pm√(4*7)`

• 
  `\sf =\pm √(4) * √(7)`

• 
  `\sf =\pm2√(7)`

Therefore, the zeros of the equation 2x² + 14 = 70 are x = 2√7 and x = -2√7.

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