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The half-life of is bromine-80 is 17.6 min. How long will it take for the activity of this isotope to drop from to 160 mCi to 10 mCi?

A. 88 min
B. 106 min
C. 70 min
D. 17.6 min
E. 35 min
F. 53 min

User PunyFlash
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1 Answer

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Final answer:

It will take 70 minutes for the activity of bromine-80 to drop from 160 mCi to 10 mCi.

Step-by-step explanation:

To determine how long it will take for the activity of bromine-80 to drop from 160 mCi to 10 mCi, we need to calculate the number of half-lives required. The activity of a radioactive isotope decreases by half in each half-life. So, to determine the number of half-lives, we can divide the initial activity (160 mCi) by the final activity (10 mCi):

Number of Half-Lives = log2(Initial Activity/Final Activity) = log2(160/10) = log2(16) = 4

Since each half-life is 17.6 minutes, we can calculate the total time it will take for 4 half-lives:

Total Time = Number of Half-Lives x Half-Life Time = 4 x 17.6 = 70 minutes

User Vladimir Nabokov
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