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An object rolls off a 8 m tall table with a velocity of 3 and lands 6 away from the base of the table. What is the vertical acceleration of the object? (Answer must be negative!!!)

User Harry Bosh
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1 Answer

26 votes
26 votes

Answer:

-9.81 m/s/s or -4 m/s/s

Step-by-step explanation:

Technically, the only vertical component of force and therefore acceleration on the object after it leaves the table will be acceleration due to gravity. So we can say the value of acceleration is g, -9.81m/s/s.

Though after checking your parameters, maybe you are on another planet with a different gravitation constant.

in this case, assuming your other values are in the standard m/s and m, we can determine how long the ball should be in the air to land 6 meters away and thus use that to find downward acceleration.

6m = 3m/s • t

2s = t

8 = 1/2 g • (2)^2

2m/s/s = 1/2 g

4 m/s/s = g

this would approximate to doing this experiment on mercury

User Balkaran Singh
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