Question

Pls help quickly 100 points

Answer 1

Car A's value follows an exponential decay model with the function
`\(f(x) = 18390 * (0.88)^x\)`. After 9 years, its value is approximately $13,215.64. Car B's linear model is
`\(g(x) = -750x + 18500\)`, and its value after 9 years is $11,850.

Car A:

Part A: Circle one. The function of Car A is LINEAR or EXPONENTIAL.

- Answer: EXPONENTIAL

Part B: Create a function to describe the value.

- Answer:
`\(f(x) = 18390 * (0.88)^x\)`

Part C: When x = 9, what is the value of f(x)? (Show your work)

- Answer:
`\(f(9) = 18390 * (0.88)^9 \approx 13,215.64\)`

Car B:

Part A: Circle one. The function of Car B is LINEAR or EXPONENTIAL.

- Answer: LINEAR

Part B: Create a function to describe the value.

- Answer:
`\(g(x) = -750x + 18500\)`

Part C: When x = 9, what is the value of g(x)? (Show your work)

- Answer:
`\(g(9) = -750 * 9 + 18500 = 11850\)`

Note: The given formulas y = mx + b and
`\(f(x) = ab^x\)` were not used as they are not appropriate for Car B, which exhibits a linear trend.