Final answer:
Using Boyle's Law, the volume of an 8.00-liter gas at 6.00 atm, when the pressure is reduced to 2.00 atm, will increase to 24.00 liters.
Step-by-step explanation:
The student's question is asking about the effect on the volume of a gas when the pressure it is subjected to is changed.
According to Boyle's Law, for a fixed amount of an ideal gas kept at a constant temperature, the pressure and volume of the gas are inversely proportional.
So when the pressure is reduced, the volume will increase, and vice versa.
To solve this specific problem, we can set up a proportion based on Boyle's Law, which states that P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given an initial pressure (P1) of 6.00 atm and an initial volume (V1) of 8.00 liters, and a final pressure (P2) of 2.00 atm, the final volume (V2) can be calculated by rearranging the equation to V2 = (P1V1) / P2.
By plugging the given values into the equation, we get:
V2 = (6.00 atm × 8.00 L) / 2.00 atm
= 24.00 L.
Therefore, the new volume of the gas when the pressure is reduced to 2.00 atm will be 24.00 liters.