Question

What are the concentrations of H30+ and OH in each of the following? 4. 3.52 M NaOH = 0.310 M = O[OH-] = 3.52 M, H0+1 = 3.52 M O[OH-] = 3.52 M, (1.0+) = 2.84 x 10-15 M 0 [OH-] = 0.284 M, (7,0+] = 3.52

Answer 1

In a 3.52 M NaOH solution, the [OH-] concentration is 3.52 M and the [H3O+] concentration is 2.84 × 10^-15 M, calculated using the ion product of water.

Step-by-step explanation:

To calculate the concentrations of H3O+ and OH- in a 3.52 M NaOH solution, we need to consider that NaOH is a strong base.

It dissociates completely in water, meaning that the concentration of OH- ions will be equal to the concentration of NaOH, which is also 3.52 M.

To find the H3O+ concentration, we use the ion product of water (Kw), which at 25 °C is 1.0 × 10-14.

The formula to find the H3O+ concentration is: [H3O+] = Kw / [OH-].

Plugging in the known values:

[H3O+] = 1.0 × 10-14 / 3.52 M

= 2.84 × 10-15 M.

Therefore, in a solution of 3.52 M NaOH, the concentration of hydroxide ions [OH-] is 3.52 M and the concentration of hydronium ions H3O+ is 2.84 × 10-15 M.