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3 Cu + 8HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O

In the above equation how many moles of NO can be made when 6.2 moles of HNO3 are consumed?

User Andselisk
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1 Answer

6 votes

Final answer:

The number of moles of NO that can be made when 6.2 moles of HNO3 are consumed in the given chemical equation is 1.55 moles.

Step-by-step explanation:

In the given balanced chemical equation:
3 Cu + 8 HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O

It is stated that 6.2 moles of HNO3 are consumed. According to the stoichiometry of the equation, for every 8 moles of HNO3 consumed, 2 moles of NO are produced. This means that for 6.2 moles of HNO3 consumed, the number of moles of NO can be calculated as follows:

(6.2 mol HNO3) x (2 mol NO / 8 mol HNO3) = 1.55 mol NO

Therefore, 1.55 moles of NO can be made when 6.2 moles of HNO3 are consumed.

User Jason Warner
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