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A ball thrown straight up in the air with an initial velocity of 15 m/s. What is the maximum height achieved by the ball at the top of its flight

User Matt Ridge
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Final answer:

The maximum height achieved by the ball thrown straight up with an initial velocity of 15 m/s is calculated using the kinematic equation and is found to be 11.48 meters.

Step-by-step explanation:

Calculating the Maximum Height of a Ball Thrown Upwards

To calculate the maximum height achieved by a ball thrown straight up in the air with an initial velocity of 15 m/s, we can use the kinematic equation for vertical motion under gravity:

h = v^2 / (2g)

where h is the maximum height, v is the initial vertical velocity, and g is the acceleration due to gravity (approximated as 9.8 m/s^2 on the surface of the Earth).

Plugging in the values:

Initial velocity, v = 15.0 m/s

Acceleration due to gravity, g = 9.8 m/s^2

We get:

h = (15.0 m/s)^2 / (2 × 9.8 m/s^2)

h = 225 m^2/s^2 / 19.6 m/s^2

h = 11.48 m

The maximum height achieve by the ball at the top of its flight is 11.48 meters.

User Luca Corsini
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