Final answer:
The maximum height achieved by the ball thrown straight up with an initial velocity of 15 m/s is calculated using the kinematic equation and is found to be 11.48 meters.
Step-by-step explanation:
Calculating the Maximum Height of a Ball Thrown Upwards
To calculate the maximum height achieved by a ball thrown straight up in the air with an initial velocity of 15 m/s, we can use the kinematic equation for vertical motion under gravity:
h = v^2 / (2g)
where h is the maximum height, v is the initial vertical velocity, and g is the acceleration due to gravity (approximated as 9.8 m/s^2 on the surface of the Earth).
Plugging in the values:
Initial velocity, v = 15.0 m/s
Acceleration due to gravity, g = 9.8 m/s^2
We get:
h = (15.0 m/s)^2 / (2 × 9.8 m/s^2)
h = 225 m^2/s^2 / 19.6 m/s^2
h = 11.48 m
The maximum height achieve by the ball at the top of its flight is 11.48 meters.