Final answer:
The percent of the total area under the standard normal curve between z-scores of -1.5 and -0.65 is found by subtracting the area to the left of z=-1.5 from the area to the left of z=-0.65, which equals 0.1910 or 19.10% when expressed as a percentage.
Step-by-step explanation:
To find the percent of the total area under the standard normal curve between z=-1.5 and z=-0.65, we refer to a z-table which shows the area under the curve to the left of a given z-score. For z=-1.5, find the corresponding area on the z-table. For z=-0.65, again find the respective area.
The area to the left of z=-1.5 is typically found to be approximately 0.0668, and the area to the left of z=-0.65 is about 0.2578. To determine the area between these two z-scores, subtract the smaller area from the larger area:
Area between z=-1.5 and z=-0.65 = Area to the left of z=-0.65 - Area to the left of z=-1.5
= 0.2578 - 0.0668
= 0.1910
To express this as a percent, multiply by 100:
(0.1910 × 100)
= 19.10%
Therefore, the percent of the total area under the standard normal curve between z=-1.5 and z=-0.65 is 19.10%.