Question

A small angle prism deviates a narrow beam of light by 1.3degree . the refractive index is 1.62 and the angle of prism in degree is?

Answer 1

The angle of the prism is approximately 1.16 degrees.

Step-by-step explanation:

To find the angle of the prism, we can use Snell's Law, which relates the angles of incidence and refraction to the refractive indices of the two media involved. In this case, the angle of deviation is given as 1.3 degrees.

We can use the formula:

n = sin((a + b)/2) / sin(a/2)

where n is the refractive index of the prism, a is the angle of incidence, and b is the angle of refraction. Rearranging the formula, we can solve for a:

a = 2 * sin^(-1)((n * sin(1.3))/1.62)

Substituting the given values, we find that the angle of the prism is approximately 1.16 degrees.