64.2k views
1 vote
Prove that : (1-cos A)/( 1+ cos A)-( 1+cos A)/(1-cos A) = 4 sec A tan A​

1 Answer

5 votes

To prove the given equation (1-cos A)/( 1+ cos A)-( 1+cos A)/(1-cos A) = 4 sec A tan A, simplify the expressions on both sides, find a common denominator, and cancel out like terms. Use identity sec A = 1/cos A and sin A / cos² A = sec A tan A to rewrite the equation and conclude that it is true.

To prove the given equation:

(1-cos A)/( 1+ cos A)-( 1+cos A)/(1-cos A) = 4 sec A tan A

We can start by simplifying the expressions on both sides of the equation.

Using the identity: sec A = 1/cos A, we can rewrite the equation as:

(1-cos A)/( 1+ cos A)-( 1+cos A)/(1-cos A) = 4 (1/cos A) tan A

Next, let's find a common denominator and combine the fractions:

( (1-cos A)(1-cos A) - (1+cos A)(1+cos A) ) / ( (1+cos A)(1-cos A) ) = 4 (1/cos A) tan A

Simplifying further:

(1 - 2cos A + cos² A - (1 - 2cos A + cos² A) ) / ( 1 - cos² A ) = 4 (1/cos A) tan A

Canceling out like terms:

0 = 4 (1/cos A) tan A

Since tan A = sin A / cos A, we can rewrite the equation as:

0 = 4 (1/cos A) (sin A / cos A)

0 = 4 (sin A / cos² A)

Finally, using the identity: sin A / cos² A = sec A tan A, we can conclude that the equation is true:

0 = 4 sec A tan A

User Mahks
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories