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Solution of zn=zn(oh)4-2+h2 in basic solution of redox balance reaction

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In a basic solution, the balanced redox reaction is Zn + 4OH⁻ + 2H₂O → Zn(OH)₄²⁻ + 2H₂, ensuring conservation of atoms and charges.

To balance the redox reaction Zn + Zn(OH)₄²⁻ + H₂ in a basic solution, we follow these steps:

1. Write the Unbalanced Equation: Zn + Zn(OH)₄²⁻ + H₂ → ?

2. Assign Oxidation States: Identify the oxidation states of each element. Zinc (Zn) goes from 0 to +2, and hydrogen (H) goes from +1 to 0.

3. Write Half-Reactions:

- Oxidation Half-Reaction: Zn → Zn²⁺

- Reduction Half-Reaction: 2H₂O + H₂ → 2OH⁻

4. Balance Atoms: Balance the number of atoms in each half-reaction.

5. Balance Charges: Add electrons to one side to balance the charges in each half-reaction.

6. Make Electrons Equal: Multiply the half-reactions to make the number of electrons equal.

7. Combine Half-Reactions: Add the balanced half-reactions together.

8. Simplify and Check: Ensure that the equation is balanced in terms of atoms and charges.

The balanced redox reaction in basic solution is:

Zn + 4OH⁻ + 2H₂O → Zn(OH)₄²⁻ + 2H₂

The question probable may be;

What is the balanced redox reaction in a basic solution for the given equation: Zn + Zn(OH)₄²⁻ + H₂ → ?

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