To complete Table 1.1 for test-tube B, subtract 5.0 cm³ (the volume of distilled water) from 10 cm³ (the total volume needed) to find that 5.0 cm³ of the 4% glucose solution should be added.
Step-by-step explanation:
The question requires completing Table 1.1 by calculating the volume of 4% glucose solution used in test-tube B. Given that test-tubes A and C have specific volumes of the 4% glucose solution and distilled water, it is likely expected that the three test tubes should contain solutions of varying concentrations made up to the same total volume.
For test-tube A, 10 cm³ of the 4% glucose solution are mixed with 0 cm³ of distilled water, for a total volume of 10 cm³. For test-tube C, 2.5 cm³ of the 4% glucose solution is mixed with 7.5 cm³ of distilled water for the same total volume of 10 cm³. Assuming test-tube B should also have a total volume of 10 cm³, and it is already known that it contains 5.0 cm³ of distilled water, we need to find the volume of the 4% glucose solution to add to reach the total volume.
To complete the volume for test-tube B, you subtract the volume of distilled water from the total volume.
Total volume for B - Volume of distilled water = Volume of 4% glucose solution
10 cm³ - 5.0 cm³ = 5.0 cm³
Therefore, 5.0 cm³ of the 4% glucose solution should be added to test-tube B.