The perimeter of the rectangle 41.95m and the correct option is E.
Area (A) = 85 square meters
Length (L) = a
Width (W) = (a - 10) meters
Area of rectangle(A) = Length (L) × Width (W)
85 = a × (a - 10)
85 = a^2 - 10a
a^2 - 10a - 85 = 0
Using quadratic equation solver :
a = 15.488088482 or a = −5.488088482
Since a cannot be negative, a = 15.49m
Therefore, Length (L) = 15.488m
Width(W) = a - 10 = (15.488 - 10) = 5.488m
Perimeter of rectangle(P) :
P = 2 (L + W)
P = 2 (15.488 + 5.488)
P = 2(20.976)
P = 41.952m
P = 41.95m
Therefore, the perimeter of the rectangle 41.95m and the correct option is E.
Question:
If the area of a rectangle is 85 square meters, and the width is ten meters
shorter than the length, find the perimeter of the rectangle in meters. Round
your answer to two decimal places.
A) 35.49 meters
B) 21.25 meters
C) 61.95 meters
D) 81.95 meters
E) 41.95 meters