Final answer:
To calculate the percentage yield of a reaction, we need to compare the actual yield with the theoretical yield. In this case, the actual yield is 4.5g of O2 and the theoretical yield of NO2 is 18g. The percentage yield is 25%.
Step-by-step explanation:
The given balanced equation is:
N2O5 ---------> 4NO2 + O2
We are given that 40g of N2O5 decomposes to produce 4.5g of O2.
To find the percentage yield, we need to compare the actual yield (4.5g) with the theoretical yield, which can be calculated using stoichiometry.
From the balanced equation, 4 moles of NO2 are produced for every mole of O2 produced.
Therefore, if 4.5g of O2 is produced, the theoretical yield of NO2 is 4 times that amount, which is 4.5g x 4 = 18g.
The percentage yield is then calculated as:
Percentage yield = (Actual Yield / Theoretical Yield) x 100%
= (4.5g / 18g) x 100%
= 25%