Question

An object travels for 20s with a constant speed of 10m/s. For the next 10s, it accelerates uniformly to 20m/s. What is the total distance travelled by the object in the 30s

Answer 1

The object will travel a total distance of 350m in the 30s.

Step-by-step explanation:

First, we can calculate the distance traveled during the first 20s when the object is moving at a constant speed of 10m/s. Distance = speed x time, so in this case, the distance is 10m/s x 20s = 200m.

Next, we can calculate the distance traveled during the next 10s when the object is accelerating uniformly from 10m/s to 20m/s. Using the equation distance =

`initial velocity x time + 0.5 x acceleration x time^2,`

where the initial velocity is 10m/s, acceleration is (20m/s - 10m/s)/10s = 1m/s^2, and time is 10s,

we have distance =

`10m/s x 10s + 0.5 x 1m/s^2 x (10s)^2`

= 150m.

Finally, to find the total distance traveled, we add the distances calculated in the two previous steps: 200m + 150m = 350m.