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Which statements are true about the polynomial function?

f(x)=x^3−x^2−4x+4

Select each correct answer.
f(−1)=0
f(x)=0 when x=−1
(x−1) is a factor of f(x)
f(x) divided by (x−1) has a remainder of 0

User Dhpiggott
by
7.1k points

1 Answer

6 votes

Explanation:

Let's evaluate each of the given statements one by one.

1. f(−1)=0

To determine if this statement is true, plug x = -1 into the function and calculate the value:


f(-1) = (-1)^3 - (-1)^2 - 4(-1) + 4


f(-1) = -1 - 1 + 4 + 4


f(-1) = -2 + 8


f(-1) = 6

So f(−1) does not equal 0, which means the statement "f(−1)=0" is false.

2. f(x)=0 when x=−1

This is essentially the same statement as the first one just worded differently. We've already determined that f(-1) is not equal to 0, so this statement is also false.

3. (x−1) is a factor of f(x)

If
(x - 1) is indeed a factor of
f(x), then the remainder when
f(x) is divided by
(x - 1) should be 0. This can be checked using synthetic division or by applying the remainder theorem which states that if a polynomial
f(x) is divided by
(x - c), the remainder is
f(c). Let's check
f(1):


f(1) = 1^3 - 1^2 - 4(1) + 4


f(1) = 1 - 1 - 4 + 4


f(1) = 0

Since
f(1) = 0,
(x - 1) is indeed a factor of
f(x), so this statement is true.

4. f(x) divided by (x−1) has a remainder of 0

From the previous statement, we know
(x - 1) is a factor of
f(x), so dividing
f(x) by
(x - 1) should indeed give a remainder of 0. Therefore, this statement is also true.

In summary, only the third and fourth statements are true:

- (x−1) is a factor of f(x)

- f(x) divided by (x−1) has a remainder of 0

User Hurelhuyag
by
7.6k points