Question

Calculate delta hf^0 of hpo3 given the data below. p4o10 + 4hno3 —> 4hpo3 + 2n2o5

Answer 1

To calculate the change in enthalpy (ΔH) for the given reaction P4O10 + 4HNO3 → 4HPO3 + 2N2O5, we need to calculate the enthalpy change for each individual step and then subtract the sum of the reactants from the sum of the products.

Step-by-step explanation:

To calculate the change in enthalpy (ΔH) for the given reaction, we need to calculate the enthalpy change for each individual step and then subtract the sum of the reactants from the sum of the products.

Step 1: Calculate the enthalpy change for the reaction P4O10 + 4HNO3 → 4HPO3 + 2N2O5

Using the given data:

Reactants: P4O10 = 35.6 g, HNO3 = 4.77 g

Products: HPO3 = ?, N2O5 = ?

From the balanced equation, we can see that there is a 1:1 mole ratio between P4O10 and HPO3, and a 4:1 mole ratio between HNO3 and HPO3. This allows us to calculate the moles of HPO3 produced:

moles of HPO3 = (35.6 g P4O10) / (P4O10 molar mass) * (HPO3 molar mass) / (1 mole P4O10)

Next, we can calculate the moles of N2O5 produced:
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