Final answer:
To determine how much will dissolve at 1.0 atm of pressure, we can use Henry's law. At 1.0 atm of pressure, approximately 1.67 g of the solute will dissolve in 1 L of water.
Step-by-step explanation:
To determine how much will dissolve at 1.0 atm of pressure, we can use Henry's law. Henry’s law states that the concentration of a gas in a liquid is directly proportional to the pressure of the gas above the liquid. Mathematically, this can be represented as:
C = kP
where C is the concentration of the gas, k is the Henry’s law constant, and P is the pressure of the gas.
In this case, we are given the concentration at 0.8 atm of pressure (2.5 g dissolved in 1.2 L of water). To find the concentration at 1.0 atm of pressure, we can set up a proportion:
C1/C2 = P1/P2
Substituting the given values, we get:
C1/(2.5 g/1.2 L) = 0.8 atm/1.0 atm
Solving for C1, we find:
C1 = (2.5 g/1.2 L) * 0.8 atm/1.0 atm
C1 = 1.67 g/L
Therefore, at 1.0 atm of pressure, approximately 1.67 g of the solute will dissolve in 1 L of water.