a = 5 = first term
d = 3 = common difference
tn = nth term
tn = a + d(n-1)
tn = 5 + 3(n-1)
Plug in n = 100 to find the 100th term.
t100 = 5 + 3(100-1)
t100 = 5 + 3(99)
t100 = 5 + 297
t100 = 302
The 100th term is 302
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