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Amy, Manuel, and Lamar have a total of $92 in their wallets. Amy has $10 more than Manuel. Lamar has 4 times what Amy has. How much do they have in their wallets?

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Answer:

Let's assign variables to represent the amounts of money each person has:

Let A represent the amount Amy has.

Let M represent the amount Manuel has.

Let L represent the amount Lamar has.

We are given the following information:

1. Amy has $10 more than Manuel, so A = M + $10.

2. Lamar has 4 times what Amy has, so L = 4A.

3. The total amount of money they have is $92, so A + M + L = $92.

Now we can solve the system of equations to find the values of A, M, and L.

Substituting the value of A from equation 1 into equation 3:

(M + $10) + M + 4(M + $10) = $92

M + $10 + M + 4M + $40 = $92

6M + $50 = $92

6M = $92 - $50

6M = $42

M = $42 / 6

M = $7

Using the value of M, we can find A:

A = M + $10

A = $7 + $10

A = $17

Finally, using the value of A, we can find L:

L = 4A

L = 4($17)

L = $68

Therefore, Amy has $17, Manuel has $7, and Lamar has $68 in their wallets.

User Vithani Ravi
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