Question

A 52.8g sample of brass, which has a specific heat capacity of 0.375 j*g^-1*C^-1 , is put into a calorimeter (see sketch at right) that contains 250.0g of water. The temperature of the water starts off at 18.0 C . When the temperature of the water stops changing it's 19.3C . The pressure remains constant at 1 atm .

Answer 1

To calculate the specific heat capacity of the metal, use the formula Cp(metal) = (m(water) * Cp(water) * (T(final) - T(initial))) / (m(metal) * (T(initial, water) - T(final, water))). Plugging in the given values and simplifying gives a specific heat capacity of -2.44 J/g°C.

To calculate the specific heat capacity of the metal, we can use the formula:

Cp(metal) = (m(water) * Cp(water) * (T(final) - T(initial))) / (m(metal) * (T(initial, water) - T(final, water)))

Where:

Cp(metal) = specific heat capacity of the metal

m(water) = mass of water

Cp(water) = specific heat capacity of water

T(final) = final temperature of the system

T(initial) = initial temperature of the metal

(T(initial, water) - T(final, water)) = temperature change of the water

Plugging in the given values:

m(water) = 64.0 g

Cp(water) = 4.18 J/g°C

T(final) = 39°C

T(initial) = 75°C

(T(initial, water) - T(final, water)) = 50.0°C

Substituting the values in the formula gives:

Cp(metal) = (64.0 g * 4.18 J/g°C * (39°C - 75°C)) / (34.5 g * (75°C - 39°C))

Simplifying further:

Cp(metal) = -2.44 J/g°C

Therefore, the specific heat capacity of the metal is -2.44 J/g°C.