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The weight of a body with a density of 7 g/cm³ is 2.8 N in air. The body has a density of 0.7 g/cm³ What is its weight when immersed in liquid?

User Ben Doom
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The weight of the body when immersed in liquid is equal to the weight of the liquid displaced:

Weight of body when immersed = Weight of liquid displaced = 0.0286 g = 0.0286 N

To find the weight of the body when immersed in liquid, we need to consider the buoyant force acting on the body.

The buoyant force is equal to the weight of the liquid displaced by the body.

Since the body has a density of 0.7 g/cm³, it will displace a volume of liquid equal to its own volume when immersed.

The weight of this volume of liquid can be calculated using the density of the liquid and the volume of the body.

Let's use the formula:

Buoyant force = Weight of liquid displaced = Density of liquid × Volume of body

Given:

Density of the body = 7 g/cm³

Weight of the body in air = 2.8 N

Density of the liquid = 0.7 g/cm³

Volume of the body = ?

Weight of the body when immersed in liquid = ?

First, we can find the volume of the body using the formula:

Mass = Density × Volume

So, Volume = Mass / Density

Since we are given the density of the body and its weight in air, we can calculate the mass of the body:

Weight = Mass × Gravity

Mass = Weight / Gravity

Now, let's find the mass of the body:

Mass = 2.8 N / 9.8 m/s² = 0.2857 kg

Next, we can find the volume of the body:

Volume = Mass / Density = 0.2857 kg / 7 g/cm³ = 0.0408 cm³

Now, let's find the weight of the liquid displaced by the body:

Weight of liquid displaced = Density of liquid × Volume of body

= 0.7 g/cm³ × 0.0408 cm³

= 0.0286 g

Finally, the weight of the body when immersed in liquid is equal to the weight of the liquid displaced:

Weight of body when immersed = Weight of liquid displaced = 0.0286 g = 0.0286 N

User Bharadwaj
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