The equation of the line passing through the points (-6,7), (-4,2), (-2,-3), and (0,-8) is
, expressed in fully simplified slope-intercept form.
To find the equation of the line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we first need to calculate the slope using the given points.
![\[ \text{Slope (m)} = \frac{\text{change in } y}{\text{change in } x} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/5rvuah385vv5n25rwxyfofnpiur744qr1c.png)
Using the points (-6,7) and (0,-8):
![\[ m = (-8 - 7)/(0 - (-6)) = (-15)/(6) = -(5)/(2) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/zct2vlil4e2tbil6p6mfehkcige32hzptq.png)
Now, pick one of the points (let's use (-6,7)) and substitute it into the slope-intercept form to find b:
![\[ 7 = -(5)/(2)(-6) + b \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/tj0525k80ouo8q36qew9qwyjdoneek76ea.png)
Solving for b:
![\[ 7 = 15 + b \]\[ b = -8 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/329w6sje2qacry7yt2gplq2sdhj4819r0n.png)
Therefore, the equation of the line is:
![\[ y = -(5)/(2)x - 8 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/1gg47hooa3risyqynzn9j2kbjua7qpnbp5.png)