By setting up a system of equations using the cost and sales information, it is determined that 16 bracelets and 21 necklaces were sold at the flea market.
To solve the problem of determining how many bracelets and necklaces were sold, we can use a system of equations based on the given information:
You sell bracelets for $2 each and necklaces for $3 each.
You collected a total of $95.
The total number of jewelry items sold is 37.
Let's define the variables:
Let b = number of bracelets sold
Let n = number of necklaces sold
We can set up the following two equations:
b + n = 37 (total number of bracelets and necklaces)
2b + 3n = 95 (total sales in dollars)
Now, we can solve this system of equations. Multiply the first equation by 2:
2b + 2n = 74
Subtract this equation from the second equation:
2b + 3n = 95
- (2b + 2n = 74)
This yields n = 21.
Now we know 21 necklaces were sold.
To find the number of bracelets sold, substitute the value of n back into the first equation:
b + 21 = 37
b = 37 - 21
b = 16
Thus, 16 bracelets and 21 necklaces were sold.
Question:
You sell bracelets for $2 each and necklaces for $3 each at a local flea market. You collect $95, selling a total of 37 jewelry items. How many of each type of jewelry did you sell?