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Write the equation of line parallel to Y=4x-2 and goes thru (8, 4)

User Guzmonne
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Answer:

The equation \(y = 4x - 2\) represents a line with a slope of 4 (since the

coefficient of \(x\) is 4).

For a line parallel to \(y = 4x - 2\), it should have the same slope as 4. Lines that are parallel have the same slope but different y-intercepts.

Now, using the point-slope form of a line (\(y - y_1 = m(x - x_1)\)) where \((x_1, y_1)\) is the given point (8, 4) and \(m\) is the slope (4):

\(y - 4 = 4 \cdot (x - 8)\)

\(y - 4 = 4x - 32\)

Now, solve for \(y\):

\(y = 4x - 32 + 4\)

\(y = 4x - 28\)

Therefore, the equation of the line parallel to \(y = 4x - 2\) and passing through the point (8, 4) is \(y = 4x - 28\).

Explanation:

User BADAOUI Mohamed
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